averygoodun42: (Default)
averygoodun42 ([personal profile] averygoodun42) wrote2013-07-09 07:02 pm
Entry tags:

*flails*

OhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgodOhgod...

I am so screwed.

I just took the practice algebra test, and I got 41%. Functions and graphing kicked my butt to the door and into the gutter. (I shouldn't count the questions on complex numbers as I haven't reviewed that material yet, but needless to say that added to my miserable outcome.)

The worst bit is that some of the answers really confuse me. Like, why is 2+x+y a factor of 4-(x+y)^2? I do not understand that. At all.

And how does (3(-1)^n-1)/2^n create the geometric sequence 3/2, -3/4, 3/8? Got it. Never mind.

(I also really, really need to review sequencing of all ilks. Only learned sigma's meaning today. Yikes.)

I am so, so screwed.

*meebbles*
ext_76688: (lune)

[identity profile] septentrion1970.livejournal.com 2013-07-10 05:22 am (UTC)(link)
Will it be a major set-back to your studies? I hope not! *hugs*

[identity profile] randomchris.livejournal.com 2013-07-10 10:07 am (UTC)(link)
For that one, think of (x+y) as being one number, call it z for now, because it's the same term in both equations.

So why is (2 + z) a factor of (4 - z^2)?

Because (2 + z) ( 2 - z) = 4 + 2z - 2z + z^2
The 2z terms cancel out, giving 4 - z^2.

It works when you put in numbers: if we have z = 10, then 4 - z^2 = -96, and 2 + z = 12. And 12 is a factor of -96. But algebra helps prove that it's true no matter what z you start with.

Does that help at all?

[identity profile] averygoodun.livejournal.com 2013-07-11 02:34 am (UTC)(link)
That helps quite a lot, actually. A much more intuitive way of looking at it than the explanation another friend gave. Thanks!

[identity profile] evieeros.livejournal.com 2013-07-11 08:42 pm (UTC)(link)
Just an FYI, if you ever find yourself in need of a study session or tutoring I wanted to let you know that I am a professional math tutor. I'd be happy to help you for free with short questions like the ones posted in this journal (seems like [livejournal.com profile] randomchris has it covered here!) and I would also give you a discount on a live tutoring session (phone, skype, email and chat, etc). Just send me a PM if you're interested! And of course Best of Luck!